Q21.26 P - Chemistry: Molecular Nature Of Matter And Change

Question

When a piece of metal A is placed in a solution containing ions of metal , metal plates out on the piece of A. 

(a) Which metal is being oxidized? 

(b) Which metal is being displaced? 

(c) Which metal would you use as the anode in a voltaic cell incorporating these two metals? 

(d) If bubbles of  ${\mathbf{\text{H}}}_{\mathbf{\text{2}}}$form when is placed in acid, will they form if A is placed in acid? Explain

Step-by-Step Solution

Answer

(a) The metal is oxidising.

(b) Metal is in the process of being relocated.

(c) As an anode, Metal A will be employed.

(d) If metal A is added to the acid, ${\text{H}}_{\text{2}}$bubbles will occur. Because metal A is more reactive than metal B, this is the case.

Step 1: Definition of Chemical Change and Electrical Work

Electrochemistry is a discipline of physical chemistry concerned with the relationship between electrical potential as a quantifiable and quantitative phenomenon and recognisable chemical change, with electrical potential as an outcome of a specific chemical change or vice versa.

 

Step 2: Which metal is being oxidized?

(a)Metal A is being oxidised, while metal  is being reduced from an ion to a solid metal form.  

 

Step 3: Which metal is being displaced?

(b) Because metal is oxidised, it transforms from a solid metal to ions in the solution, and it is being displaced.

 

Step 4: Which metal would you use as the anode in a voltaic cell?

(c) Because metal A quickly oxidises when coupled with metal , it will be employed as an anode.

 

Step 5: If A is placed in acid? Explain.

(d) Bubbles of ${\text{H}}_{\text{2}}$will form if metal A is placed in the acid . This is due to the fact that metal  A is more reactive than metal B , as it easily oxidises when exposed to metal B ions.