Q21. - Algebra 2

Question

Write an equation in slope-intercept form for each graph.

Step-by-Step Solution

Answer

The equation of the required straight line in slope-intercept form is $y=-4$.

Step 1 – State the concept

The slope intercept form of a straight-line equation is $y=mx+c$ where $m$ is the slope and $c$ is the y-intercept.

 

The slope of a horizontal line is $0$.

 

The y-intercept is the value of $y$ at the point where the line crosses the $y$-axis.

Step 2 – List the given data

It is clear, from the graph, that the line is parallel to x-axis and thus, is a horizontal line.

 

It is also clear that the line crosses the y-axis at the point $\left(0,-4\right)$.

Step 3 – Write the equation

The given line is a horizontal line. Thus, its slope is $0$. So,$m=0$.

 

The line crosses the y-axis at the point $\left(0,-4\right)$. Thus, its y-intercept is $-4$. So, $c=-4$

 

Put $m=0$ and $c=-4$ in $y=mx+c$ to get,

 

$y=\left(0\right)x+\left(-4\right)$

 

$y=-4$  (Simplify)

 

So, the required equation of the straight line in slope-intercept form is $y=-4$.