Q.21
Question
The -value for a chi-square goodness-of-fit test is . The correct conclusion is
(a) reject at ; there is strong evidence that the trees are randomly distributed.
(b) reject at ; there is not strong evidence that the trees are randomly distributed.
(c) reject at ; there is strong evidence that the trees are not randomly distributed.
(d) fail to reject at ; there is not strong evidence that the trees are randomly distributed.
(e) fail to reject at ; there is strong evidence that the trees are randomly distributed.
Step-by-Step Solution
VerifiedCorrect option is
(c) reject at ; there is strong evidence that the trees are not randomly distributed.
Given in the question that, Researchers wondered whether the trees in a longleaf pine forest in Georgia are randomly distributed. To find out, they divided the forest into four equal quadrants. Then the researchers took a random sample of 100 trees and counted the number in each quadrant. Here are their data:
Table is
| Quadratic | Count |
-value is
Level of significance
The null and alternative hypotheses are:
At least one of the is incorrect
The calculation for test statistic could be done as:
| Observed value(O) | Expected value(E) |
The test statistic is:
The-value is
The -value is below the significance level. Thus, the null hypothesis is rejected. Thus at significance level there is sufficient evidence to favor the claim about the trees.
Hence, the correct option is (c).