Q20E
Question
In light of the fact that tertiary alkyl halides undergo spontaneous dissociation to yield a carbocation plus halide ion (see Problem 10-45), propose a mechanism for the following reaction.
Step-by-Step Solution
Verified Answer
The mechanism is as follows:
1Step 1: Formation of tert-butyl carbocation
This step is slow and rate determining step. A more stable tert-butyl carbocation is formed in this step. The carbocation is more stable due to hyperconjugation and it leaves behind bromide anion.
2Step 2: SN 1 pathway
During this step, HOH attacks on the carbocation, due to which loss of proton takes place. This results in the removal of the hydrogen from the carbon adjacent to the carbocation. As a result, we get the desired product.
The reaction is as follows:
Other exercises in this chapter
18E-b
Draw the electron-pushing mechanism for the propagation steps of the allylic bromination reactions below. You may omit NBS in your mechanism, and use Br∙ and Br
View solution Q 18E-C
Draw the electron-pushing mechanism for the propagation steps of the allylic bromination reactions below. You may omit NBS in your mechanism, and use Br∙ and&nb
View solution Q22E-a
Question: Name the following alkyl halides:
View solution Q22E-b
Question: Name the following alkyl halides:
View solution