Q20. - Algebra 2

Question

Find the value of each determinant.

 

20. $\left|\begin{array}{cc}-6& -2\\ 8& 5\end{array}\right|$

Step-by-Step Solution

Answer

The value of the determinant $\left|\begin{array}{cc}-6& -2\\ 8& 5\end{array}\right|=-14$.

Step 1 - Define the determinant of second-order matrix

The determinant of second order matrix is found by calculating the difference of the product of the two diagonals, that is.,  $\left|\begin{array}{cc}a& b\\ c& d\end{array}\right|=ad-bc$.

Step 2 - Find the determinant

Apply the definition of the method of finding determinant of second order

matrix $\left|\begin{array}{cc}-6& -2\\ 8& 5\end{array}\right|$.

$\left|\begin{array}{cc}-6& -2\\ 8& 5\end{array}\right|=-6\times \left(5\right)-\left(-2\right)\left(8\right)$

Step 3 - Simplify

To further simplify multiply the values first and then find the difference.

 

 $\begin{array}{c}\left|\begin{array}{cc}-6& -2\\ 8& 5\end{array}\right|=-6\times \left(5\right)-\left(-2\right)\left(8\right)\\ =-30+16\\ =-14\end{array}$