Q.2-9-24P

Question

Question. Express the following complex numbers in the  form. Try to visualize each complex number, using sketches as in the examples if necessary. The first twelve problems you should be able to do in your head (and maybe some of the others—try it!) Doing a problem quickly in your head saves time over using a computer. Remember that the point in doing problems like this is to gain skill in manipulating complex expressions, so a good study method is to do the problems by hand and use a computer to check your answers.

 

24.  (1-i3)21(i-1)38

Step-by-Step Solution

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Answer


Answer:

 

The value of the expression (1-i3)21(i-1)38 is 4i.

 

The graph of 4i.   is shown below:



1Step 1: Given information

The given complex number is (1-i3)21(i-1)38 .

2Step 2: Definition of complex numbers

The numbers that are presented in the form of a+i b, where, a,b,  are real numbers and i  is an imaginary number called complex numbers.

3Step 3: Find the value of z 1

Let the given number be  z=(1-i3)21(i-1)38                ……. (1)

 

The standard form of the complex number is x+iy .

 

Let z1=1-i3 .

 

The modulus of z1  is  r1=1+3. So, r1 =2.

 

The argument of z1   is θ1=-arctan(3) .

 

 θ1=-π3

 

Hence, z1=2e(-π/3)     … (2)

4Step 4: Find the value of z 2

Let z2=i-3 .

 

The modulus of z2 is r2=1+1.

r2=2

 The argument of z2 is θ2=π-arctan11.

 

So θ2=3π4 .

 

Hence, z2=2e(3πi/4)             … (3)

5Step 5: Find the value of the complex number z

Put the equations (2) and (3) in the equation (1).

 z=2e(-πi/3212e(3πi/4)38  =(2)21(2)19×e(-πi/321e(3πi/4)38×1e(3πi/4)2 =(2)2×e(-7πie(27πi)×e-3πi/2  =(2)2×cos(-7π)+isin(-7π)cos(-27π)+isin(27π)×e-3πi/2

Solve further,

 

 z=(2)2cos-3π2+isin-3π2 z=4i

 

Hence, the value of the complex number is 4i .

 

6Step 6: Plot the complex number.


The graph of  z=4as follows: