Q1E

Question

In Problems 1-10, use a substitution y=xr to find the general solution to the given equation for x>0.

x2y"(x)+6xy'(x)+6y(x)=0

Step-by-Step Solution

Verified
Answer

The general solution to the given equation x2y"(x)+6xy'(x)+6y(x)=0 is y=c1x-2+c2x-3.

1Define Cauchy-Euler equations:

In mathematics, a Cauchy problem is one in which the solution to a partial differential equation must satisfy specific constraints specified on a hypersurface in the domain. An initial value problem or a boundary value problem is both examples of Cauchy problems. The equation will be in the form of ax2y"+bxy'+cy=0.

2Find the general solution:

Given, 

x2y"(x)+6xy'(x)+6y(x)=0 

Let L be the differential operator defined by the left hand side of the equation.

L[y](x)=x2y"+6xy'+6y

w(r,x)=xr


By substituting you get,

L[y](x)=x2(xr)"+6x(xr)'+6xr 

=x2(r(r-1)) xr-2+6x(r)xr-1+6xr  

=(r2-r) x+6rxr +6xr

=(r2+5r+6) xr


Solving the indicial equation.

r2+5r+6 =0

(r+3) (r+2)=0


The two distinct roots are,

r1=-2

r2=-3

There are two linearly independent solutions.

y1=c1x-2

y2=c2x-3

The general solution is y=c1x-2+c2x-3.