Q19P
Question
When the NMR spectrum of an alcohol is run in dimethyl sulfoxide (DMSO) solvent rather than in chloroform, exchange of the O-H proton is slow and spin-spin splitting is seen between the O-H proton and C-H protons on the adjacent carbon. What spin multiplicities would you expect for the hydroxyl protons in the following alcohols?
- 2-Methyl-2-propanol
- Cyclohexanol
- Ethanol
- 2-Propanol
- Cholesterol
- 1-Methylcyclohexanol
Step-by-Step Solution
VerifiedThe spin multiplicities of the hydroxyl proton in the given alcohols are
- Unsplit
- Doublet
- Triplet
- Doublet
- Unsplit
In the NMR spectrum, the spin multiplicities of alcohol under slow exchange conditions are different for primary, secondary, and tertiary alcohols. These are: unsplit for tertiary, doublet for secondary, and triplet for primary alcohol.
a. Here, 2-Methyl-2-propanol is a tertiary alcohol ( ). We know the –OH signal of tertiary alcohol is unsplit.
2-Methyl-2-propanol
b. Here, Cyclohexanol is a secondary alcohol ( ). We know the signal of secondary alcohol gets splits into a doublet.
Cyclohexanol
C. Here, Ethanol is a primary alcohol ( ). We know the signal of primary alcohol gets splits into a triplet. So, the -OH signal appears as a triplet.
Ethanol
d. Here, 2-Propanol is a secondary alcohol ( ). We know the signal of secondary alcohol gets splits up into a doublet. So, the -OH absorption splits into a doublet.
2-Propanol
e. From the structure of Cholesterol, it is a secondary alcohol ( ). We know the signal of secondary alcohol gets splits up into a doublet. So, -OH absorption splits into a doublet.
Cholesterol
f. The structure of 1-Methylcyclohexanol has a tertiary alcohol ( ).
We know the signal of –OH in tertiary alcohol is unsplit.
1-Methylcyclohexanol