Q19E

Question

Coherent light with wavelength 500 nm passes through narrow slits separated by 0.340mm. At a distance from the slits large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 23.0° from the centerline?

Step-by-Step Solution

Verified
Answer

The phase difference (in radians) in the light from the two slits is 1669rad .

1Step 1: Formula for phase difference

ϕ=r*+2πλ

2Step 2: Calculate the phase difference

Given:            

                   λ=500nm=500*10-9md=0.340mm=0.340*10-3m

                  θ=23.0°

Now, the phase difference is given by

                       ϕ=r*2πλ


The path difference is given by

                            r=dsinθ

So, 

                            ϕ=dsinθ*2πλ

Plug the given,

                             ϕ=0.340*10-3*sin23°*2π500*10-9=1669rad

Thus, the phase difference (in radians) in the light from the two slits is 1669rad .