Q19 E
Question
\({{\rm{\beta }}^{\rm{ + }}}\)decay of \(^{{\rm{50}}}{\rm{Mn}}\)
Step-by-Step Solution
VerifiedThe \({\beta ^ - }\) Decay equation of \(^{50}Mn\) is \(_{25}^{50}M{n_{25}} \to _{24}^{50}C{r_{26}} + {\beta ^ + } + {\nu _c}\).
The amount of matter contained in an atom of an element is called its atomic mass.
\(A = N + Z\)
Where A is atomic mass number
Z is the number of protons in a nucleus
X is the symbol for the element
In the expression below:
\(_Z^A{X_N}\)
Z is the number of protons in a nucleus
X is the symbol for the element
We know that
\(A = N + Z\)
Where A is atomic mass number
The atomic mass of \(_{25}^{50}M{n_{25}}\) is 50 and
\(\begin{align}A &= 50\\Z &= 25\\N &= 25\end{align}\)
Thus,
\(\begin{align}A &= 50\\N &= 25 + 1\\ &= 26\\Z &= A - N\\ &= 50 - 26\\ &= 24\end{align}\)
Therefore, \({\beta ^ - }\) Decay equation of \(^{50}Mn\) is \(_{25}^{50}M{n_{25}} \to _{24}^{50}C{r_{26}} + {\beta ^ + } + {\nu _c}\).