Q.1.88 - Intermediate Algebra

Question

Locate on the number line: ⓐ $0.9$ ⓑ $-0.75$

Step-by-Step Solution

Answer

The required number line is  

(a)

(b)

Given numbers

Given numbers are $0.9,-0.75$

Procedure

(a) The decimal number $0.9$ is equivalent to$\frac{9}{10}$ a proper fraction, so $0.9$ is located between 0 and 1. On a number line, we divide the interval between 0 and 1 into 10 equal parts. Now we label the parts$0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0$ and mark $0.9$ on the number line.

(b) The decimal number $-0.75$ is equivalent to$-\frac{75}{100}=-\frac{1}{4}$, a proper fraction, so  is located between -1 and 0. On a number line, we divide the interval between -1 and 0 into 4 equal parts. Now we label the parts$-1,-0.75,-0.5,-0.25$ and mark $-0.75$ on the number line.

The line

The number lines are

(a)

(b)