Q1.77CP - Chemistry: Molecular Nature Of Matter And Change

Question

An Olympic- size pool is 50.0m long and 25.0 m wide. 

(a) How many gallons of water (d=1.0g/mL) are needed to fill the pool to an average depth of 4.8 ft? (b) What is the mass (in kg) of water in the pool?

Step-by-Step Solution

Answer

The answer is,

(a) 483114.09 gal

(b) 1831002.401 kg

Step 1: Volume of a tank

The volume of a tank is given by the product of length, breadth and height of the tank. Calculating the volume that can occupy in a tank, permits us to calculate how much water that can be carried out in a tank.

Step 2: Subpart (a)

Given, 

The length of the pool is 50.0m.

The width of the pool is 25.0m.

The depth of the pool is 4.8ft (1.46m).

The volume of the pool is calculated as shown below.

$50\mathrm{m}\times 25\mathrm{m}\times 1.46\mathrm{m}=1828.8{\mathrm{m}}^3$

Then,  $1.0{\mathrm{m}}^3=264.17\mathrm{gal}$

Therefore the amount of water required to fill in the pool is calculated as shown below.

$1828.8{\mathrm{m}}^3\times \frac{264.17\mathrm{gal}}{1.0{\mathrm{m}}^3}=483114.09\mathrm{gal}$

Step 3: Subpart (b)

It is known that, 1 gal = 3.79 kg.

Then the mass of water in the pool in kg is calculated as shown below.

$483114.09\mathrm{gal}\times 3.79=1831002.401\mathrm{kg}$