Q16E
Question
How would you prepare 1-phenyl-2-butanone, C6H5CH2COCH2CH3, from benzyl bromide, C6H5CH₂Br? More than one step is required?
Step-by-Step Solution
Verified Answer
The preparation of 1-phenyl-2-butanone, C6H5CH2COCH2CH3, from benzyl bromide, C6H5CH₂Br can be explained.
1Step 1: Formation of bonds
The metal Mg reacts with the benzyl bromide for the formation of benzyl magnesium bromide. There is a cleavage of C-Br bond and formation of C-Mg and Mg-Br bonds.
2Step 2: 1-phenyl-2-butanone formation
The reaction of propanol with benzyl magnesium bromide results in the acidification for the formation of 1-phenylbutan-2-ol.
The double bond between C and O of propanol can be converted to the single bond of C-O and O-H for the formation of O-H and C-C bonds.
The oxidation of secondary alcohol to ketone.
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