Q16E

Question

Find a general solution to the givenhomogeneous equation.  (D+1)2(D6)3(D+5)(D2+1)(D2+4)2[y]=0

Step-by-Step Solution

Verified
Answer

The general solution to the homogeneous equation is:

 y=C1ex+C2xex+C3e6x+C4xe6x+C5x2e6x+C6e5x+C7cosx+C8sinx+C9cos2x+C10sin2x

1Step 1: Homogenous Equation

A homogeneous system of linear equations is one in which all of the constant terms are zero. A homogeneous system always has at least one solution, namely the zero vector. When a row operation is applied to a homogeneous system, the new system is still homogeneous.

2Step 2: Solving of Homogenous Equation :

The given differential equation is   (D1)2(D6)(D+5)(D2+1)(D2+4)[y]=0. To solve this equation we look at its auxillary equation which is . (m+1)2(m6)3(m+5)(m2+1)(m2+4)=0

3Step 3: Solving for general equation:

The complete set of solution of auxillary equation is {1,1,6,66,5,i,i,2i,2i}

To conclude that the general solution of the given differential equation is  y=C1ex+C2xex+C3e6x+C4xe6x+C5x2e6x+C6e5x+C7cosx+C8sinx+C9cos2x+C10sin2xy=C1ex+C2xex+C3e6x+C4xe6x+C5x2e6x+C6e5x+C7cosx+C8sinx+C9cos2x+C10sin2x, where Ci(1i10)  are arbitrary constants.

 

The general solution of the given differential equation isy=C1ex+C2xex+C3e6x+C4xe6x+C5x2e6x+C6e5x+C7cosx+C8sinx+C9cos2x+C10sin2x , where Ci(1i7)  are arbitrary constant.

 

Hence, the final answer is:

 y=C1ex+C2xex+C3e6x+C4xe6x+C5x2e6x+C6e5x+C7cosx+C8sinx+C9cos2x+C10sin2x