Q16.104 CP

Question

An atmospheric chemist fills a container with gaseous N2O5 to a pressure of 125 kPa, and the gas decomposes to NO2 and O2. What is the partial pressure of PNO2, (in kPa), when the total pressure is 178 kPa?

Step-by-Step Solution

Verified
Answer

The partial pressure of NO2 is equal to 71 kPa when the total pressure is 178 kPa.

1Step 1: The chemical equation for the decomposition

Write the chemical equation for the decomposition of :

N2O5(g)NO2(g)+O2(g)

Balance the nitrogen atoms:

N2O5(g)2NO2(g)+O2(g)

Balance the oxygen atoms:

N2O5(g)2NO2(g)+12O2(g)

As a result, one mole of N2O5 breakdown produces two moles of  NO2and half a mole of O2 . As a result, the number of moles in the goods increases.

2Step 2: Determine the partial pressure of N O 2

A gas's pressure is proportional to its number of moles, and a change in the number of moles signals a change in reaction pressure. Consider x to be the drop in N2O5 pressure. Relate the pressure change in terms of the starting pressure, Pinitial , and the final pressure, Pfinal , as follows:

N2O5(g)2NO2(g)+12O2(g)Pinitial12500Pfinal125 - x 2x12x

Total Pfinal = 125 - x + 2x + 12x178kPa = 125 - x + 2x + 12xx = 35.33 kPa

Determine the partial pressure of NO2:

PNO2=2x=2×35.33kPa=71kPa

Thus, the partial pressure of NO2 is equal to 71 kPa.