Q16. - Algebra 1

Question

Write $y+4=-7\left(x-3\right)$ in slope-intercept form.

Step-by-Step Solution

Answer

The equation of the straight line for the given condition is $\mathit{y}\mathbf{=}\mathbf{-}\mathbf{7}\mathit{x}\mathbf{+}\mathbf{17}$.

Step 1. State the concept of a straight line.

The standard form of slope and intercept form of the straight line is $y=mx+c$.

Here, $m$ is the slope of the straight line and $c$ is the $y$-intercept of the equation.

Step 2. State the equation of a line slope-point form.

The standard form of slope and point form of the straight line is $y-y_1=m\left(x-x_1\right)$

Here $m$ is the slope of the straight line and is the point from which the straight line passes.

 $$\begin{gathered} \left(x_1,y_1\right)=\left(3,-4\right) \\ m=-7 \end{gathered}$$

Step 3. Simplify the equation to get the required equation.

Converting the given equation in the standard form.

$$\begin{gathered} y+4=-7\left(x-3\right) \\ y+4-4=-7x+21-4 \\ y=-7x+17 \end{gathered}$$

The equation of the straight line is $y=-7x+17$.