Q16 P-c.
Question
Sight along the C2-C1 bond of 2-methylpropane (isobutane).
(c) Make a graph of energy versus angle of rotation around the C2-C1 bond.
Step-by-Step Solution
Verified Answer
(c)
1Graph of energy versus angle of rotation
The eclipsed conformation is less stable than the staggered conformation. This is because it comprises more potential energy due to the torsional strain.
2Graph of energy versus angle of rotation around the C2-C1 bond
(c) A particular molecule’s stability is inversely related to its energy. Hence, the atom possessing less energy is more stable. The atom with high energy is least stable. The graph of energy versus the angle of rotation can be given as:
Graph of energy versus angle of rotation
Other exercises in this chapter
Q. 3-3-16 P-b
Sight along the C2-C1 bond of 2-methylpropane (isobutane). (b) Draw a Newman projection of the least stable conformation.
View solution Q. 3-3-16 P-a
Sight along the C2-C1 bond of 2-methylpropane (isobutane).(a) Draw a Newman projection of the most stable conformation.
View solution Q16 P-d.
Sight along the C2-C1 bond of 2-methylpropane (isobutane). (d) Assign relative values to the maxima and minima in your graph, given thatAn eclipsing
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Draw a Newman projection along the C2 -C3 bond of the following conformation of 2,3-dimethylbutane, and calculate a total strain energy:
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