Q16. - Algebra 2

Question

Find the value of each determinant.

 

$\left|\begin{array}{cc}8& 5\\ 6& 1\end{array}\right|$

Step-by-Step Solution

Answer

The value of the determinant $\left|\begin{array}{cc}8& 5\\ 6& 1\end{array}\right|=-22$.

Step 1 - Define the determinant of second-order matrix

The determinant of second order matrix is found by calculating the difference of the product of the two diagonals, that is.,  $\left|\begin{array}{cc}a& b\\ c& d\end{array}\right|=ad-bc$.

Step 2 - Find the determinant

Apply the definition of the method of finding determinant of second order

matrix $\left|\begin{array}{cc}8& 5\\ 6& 1\end{array}\right|$.

$\left|\begin{array}{cc}8& 5\\ 6& 1\end{array}\right|=8\times \left(1\right)-5\left(6\right)$

Step 3 - Simplify

To further simplify multiply the values first and then find the difference.

$\begin{array}{c}\left|\begin{array}{cc}8& 5\\ 6& 1\end{array}\right|=8\times \left(1\right)-5\left(6\right)\\ =8-30\\ =-22\end{array}$