Q14.89P - Chemistry: Molecular Nature Of Matter And Change

Question

One similarity between B and Si is the explosive combustion of their hydrides in air. Write balanced equations for the combustion of ${\mathbf{B}}_{\mathbf{2}}{\mathbf{H}}_{\mathbf{6}}$ and  ${\mathbf{Si}}_{\mathbf{4}}{\mathbf{H}}_{\mathbf{10}}$ .

Step-by-Step Solution

Answer

${\mathrm{B}}_2{\mathrm{H}}_{6\left(\mathrm{g}\right)} + 2{\mathrm{O}}_{2\left(\mathrm{g}\right)} \to {\mathrm{B}}_2{\mathrm{O}}_{3 \left(\mathrm{s}\right) }+ 3{\mathrm{H}}_2\mathrm{O}$

$2{\mathrm{Si}}_4{\mathrm{H}}_{10} + 13 {\mathrm{O}}_2 \to 8 {\mathrm{SiO}}_2 + 10 {\mathrm{H}}_2\mathrm{O}$

Step 1: Group 15 elements

Group 15 elements belonging to the nitrogen family. They include nitrogen, phosphorus, arsenic, antimony, bismuth, and moscivium.

The atomic numbers of the group 15 elements are as follows;

Nitrogen (N) = 7

Phosphorus (P) = 15

Arsenic (As) = 33           

Antimony (Sb) = 51

Moscovium (Mc) = 83

Step 2: Balanced reaction for the combustion of B 2 H 6 and Si 4 H 10

The combustion means, a chemical reaction in which a compound is reacted in the presence of air and produces heat and energy.

If hydride of boron reacted with oxygen then it will give ${\mathrm{B}}_2{\mathrm{O}}_3$ . The balanced equation for the reaction is as follows;

                                  ${\mathrm{B}}_2{\mathrm{H}}_{6\left(\mathrm{g}\right)} + 2{\mathrm{O}}_{2\left(\mathrm{g}\right)} \to {\mathrm{B}}_2{\mathrm{O}}_{3 \left(\mathrm{s}\right) }+ 3{\mathrm{H}}_2\mathrm{O}$

If when the hydride of silicon is allowed to react with oxygen then it will give silicon dioxide. The balanced equation for the reaction is as follows;

                                  $2{\mathrm{Si}}_4{\mathrm{H}}_{10} + 13 {\mathrm{O}}_2 \to 8 {\mathrm{SiO}}_2 + 10 {\mathrm{H}}_2\mathrm{O}$