Q14.162CP

Question

Bromine monofluoride (BF) disproportionates to bromine gas and bromine tri- and pentafluorides. Use the following to find ΔHorxnfor the decomposition of BrF to its elements:

3BrF(g)Br2(g)+BrF3(l)     ΔHorxn=-125.3KJ\hfill5BrF(g)2Br2(g)+BrF5(l)   ΔHorxn=-166.1KJ\hfillBrF3(l)+F2(g)BrF5(l)      ΔHorxn=-158.0KJ\hfill

Step-by-Step Solution

Verified
Answer

Enthalpy of reaction followed as:

8BrF(g)2BrF3(l)+3Br2g+F2(g)    ΔHorxn=-138.4KJ

1Step 1: Enthalpy of reaction

It is defined as the heat of the action which is calculated to find out how much energy is required by the reaction to convert it’s one more into products that is equal to the change in energy of the system. a positive value indicates the reaction is endothermic that is heat is required and a negative value indicates the reaction is exothermic that heat is released.

2Step 2: Enthalpy of the given reaction


To calculate the enthalpy of reaction when Bromine monofluoride (BF) disproportionates to bromine gas and bromine tri- and pentafluorides followed as:

 As given:

As enthalpy is equal to 

ΔHorxn=-125.3KJ-166.1KJ+158.0KJ=-138.4KJ