Q14.

Question

Write an expression that represents the total surface area (including the top and bottom) of a tower of n cubes each having a side length of s. (Do not include faces that cover each other.)


Step-by-Step Solution

Verified
Answer

Total surface area of a tower of n cubes Sn each having a side length of s is:

Sn=4s2n+2s2.

1Step 1. State the concept of total surface are of cube.

The total surface area of a cube =6s2 where s is the length of the side of each edge of the cube.

2Step 2. Find the total surface area of the given figures.

Total surface area of the figure with 1 cube,

S1=6×s2       =6s2 .

Total surface area of the figure with 2 cubes.

 S2=5×s2+5×s2      =5s2+5s2      =10s2

Total surface area of the figure with 3 cubes is given as:

S3=5×s2+4×s2+5×s2      =5s2+4s2+5s2      =14s2

 

Therefore the total surface areas are 6s2,10s2  and  14s2 respectively.

3Step 3. Identify the pattern in which the total surface area are changing with the increase of 1 cube in each figures.

First find the difference between the total surface areas of corresponding figures.

d=S2S1  =10s26s2  =4s2

And,

d=S3S2  =14s210s2  =4s2

Notice that the common difference is constant. Therefore the sequence of total surface area are in Arithmetic progression.

4Step 4. Find the general formula for the total surface area of n cubes.

Total surface area of a tower of n cubes Sn each having a side length of s is given as follows.

Sn=S1+n1d    =6s2+n14s2    =6s2+4s2n4s2Sn=4s2n+2s2

Hence the required expression.