Q14. - Algebra 1

Question

A rectangular room is $\mathbf{12}\frac{\mathbf{1}}{\mathbf{2}}$ feet wide and 14 feet long. What is the perimeter of the room?

Step-by-Step Solution

Answer

The perimeter of the rectangular room $12\frac{1}{2}\mathrm{feet}$ wide and 14 feet long is 53 feet.

Step 1. Given information.

A rectangular room is $12\frac{1}{2}\mathrm{feet}$ wide and 14 feet long.

Step 2. The perimeter of the rectangle.

The perimeter of a rectangle with length l and breadth b is denoted by $P=2\left(l+b\right)$.

Step 3. Calculations.

The perimeter of the rectangle

$$\begin{gathered} P=2(l+b) \\ =2\times \left(12\frac{1}{2}+14\right)\mathrm{feet} \\ =2\times \left(12.5+14\right)\mathrm{feet} \\ =2\times 26.5\mathrm{feet} \\ =53\mathrm{feet} \end{gathered}$$

Thus, the perimeter of the rectangular room $12\frac{1}{2}\mathrm{feet}$ wide and 14 feet long is 53 feet.