Q13.73 P

Question

What are the mole fraction and the mass percent of a solution made by dissolving 0.30 g of KI in 0.400 L of water (d = 1.00 g/mL)?

Step-by-Step Solution

Verified
Answer

The mole fraction of KI is 0.000091 and the mass percent of solution formed from KI and water is 0.075%.

1Step 1: Concentration of the Solution

Solution can be formed from the dissolution of the solute in the solvent. The solute decides the nature of the solution.

Molality can be defined as the ratio of the mass of the solute to the mass of the solution present in kilogram measure.


Molality=NumberofMolesMassoftheSolution(inkilogram)


Number of moles can be defined as the ratio of the mass of the atom/molecule and molar mass of the atom/molecule.

NumberofMoles=MassMolarMass


Mole Fraction can be defined as the ratio of the number of moles of the solute to the number of moles of solvent and number of solute.


MoleFraction=NumberofMolesofOneComponentNumberofMolesoftheSolvent+NumberofMolesofSolute


Parts by mass: It can be defined as the percentage of the ratio of the mass of solute to the total mass of the solution.


Mass%=MassofSoluteMassoftheSolution×100


Density can be defined as the ratio of the mass of the matter to the volume of the matter.


Density=MassVolume


2Step 2: Expression to calculate the Concentration

Volume of Water =0.400L=400mL

Density of the Water =1.0g/mL


DensityofWater=MassVolume1.0g/mL=Mass400mLMass=1.0g/mL×400mLMass=400g

Mass of water =400g

NumberofMoles=MassMolarMassNumberofMolesofWater=400g18g/molNumberofMolesofWater=22mol


Mass of KI  =0.30g

Molar Mass of KI  =166g/mole


NumberofMoles=MassMolarMassNumberofMolesofKI=0.30g166g/molNumberofMolesofKI=0.002mol

Number of moles of water  =22mole

Number of KI  nKI=0.002mol


MoleFraction=NumberofMolesofOneComponentNumberofMolesoftheSolvent+NumberofMolesofSoluteMoleFractionofKl=0.00222+0.002MoleFractionofKl=0.00222.002MoleFractionofKl=0.000091

Mass of solute, KI  =0.30g

Mass of solvent, water   =400g


Mass%=MassofSoluteMassoftheSolution×100=0.30g400g+0.30g×100=0.30g400.30g×100=0.075%