Q13. - Algebra 1

Question

Daniel wants to ship a set of golf clubs and several boxes of golf balls in a box that can hold up to $14$  $\mathbf{20}\mathit{p}\mathit{o}\mathit{u}\mathit{n}\mathit{d}\mathit{s}$. If the set of clubs weighs $9$ pounds and each box of golf balls weighs $\mathbf{12}\mathbf{ }\mathit{o}\mathit{u}\mathit{n}\mathit{c}\mathit{e}\mathit{s}$, how many boxes of golf balls can Daniel ship?

Step-by-Step Solution

Answer

The number of boxes of golf balls that can Daniel ship is $\mathbf{14}$.

Step1. Given

It is given that set of clubs weighs $9 pounds$ and each box of golf balls weighs $12 ounces$. 

Step2. Write the inequality for the given situation.

Let $x$ be the number of boxes of golf balls that can Daniel ship.

$1ounces$ is equal to $0.0625pounds$.

Therefore, $12ounces$ is equal to:

$12ounces=12\times 0.0625pounds$$=0.75pounds$   

Therefore, that set of clubs weighs 9 pounds and each box of golf balls weighs $0.75$pounds.

It is given that the ship can hold up to $20$ pounds.

Therefore, the inequality for the given situation is:

$9+0.75x\le 20$

The inequality for the given situation is $9+0.75x\le 20$.

Determine the number of boxes of golf balls that can Daniel ship.

Solve the inequality $9+0.75x\le 20$

$\begin{array}{c}9+0.75x\le 20\\ 0.75x\le 20-9\\ 0.75x\le 11\\ x\le \frac{11}{0.75}\\ x\le 14.667\end{array}$

Therefore, the maximum value of $x$ an integer is $14$.

Therefore, the number of boxes of golf balls that can Daniel ship is $14$.