Q13-43E

Question


How could you use H1NMR to distinguish between the following pairs of isomers?



Step-by-Step Solution

Verified
Answer

a.Ethyl cyclopropane shows no signal and pent-2-ene has two vinylic protons which show a chemical shift at 5.4-5.5δ.


b. CH3CH2OCH2CH3Produce 2 peaks one is triplet and quartet whereas CH3OCH2CH2CH3in which methyl group bonded to oxygen produce singlet unsplit absorption.


c. Each compound shows three peaks but ester produce the downfield peak due toCH2 next to oxygen.


d. Each compound has four protons two are methyl protons and two are vinyl protons

Isomer 1 produce singlet and 2nd produce 1 singlet and doublet.      


1Step-by-Step Solution Step 1 :

Nuclear magnetic resonance is the technique that is used to identify the hydrogen in the compound and produce the corresponding peaks for its detection.

2Step 2: 1 H   NMR for compound a


Ethyl cyclopropane shows no signal and pent-2-ene has two vinylic proton which shows chemical shift at 5.4-5.5δ so it is easy to distinguish isomers from each other.



Compound A

3Step 3: 1 H   NMR for compound b


CH3CH2OCH2CH3produce 2 peaks because of two kind of protons one is methyl and other is methylene one is triplet and quartet where as CH3OCH2CH2CH3  in which methyl group bonded to oxygen produce singlet unsplit absorption and its spectrum is very complex.




Compound A

4Step 4: 1 H   NMR for compound c


Each compound shows three peaks but ester produce the downfield peak due to CH2 next to oxygen as shown :




COMPOUND C

5Step 5: 1 H   NMR for compound d


Each compound has four protons two are methyl protons and two are vinyl protons Isomer 1 produce singlet and 2nd produce 1 singlet and doublet as per the structure of the isomers.




Compound D