Q13-39E - Organic Chemistry (Mcmurry)

Question

Predict the splitting pattern for each kind of hydrogen in isopropyl propanoate,${\mathbf{CH}}_{\mathbf{3}}{\mathbf{CH}}_{\mathbf{2}}{\mathbf{CO}}_{\mathbf{2}}\mathbf{CH}{\mathbf{\left(}{\mathbf{CH}}_{\mathbf{3}}\mathbf{\right)}}_{\mathbf{2}}$.

Step-by-Step Solution

Answer

Peaks produced are:

 One singlet

Two quartet

Three septate

Four doublet

Step-by-Step Solution Step 1 : Non-Equivalent and Equivalent proton

The proton which is having a different environment and all protons give different peaks is the non-equivalent proton whereas the proton sharing the same environment and all protons giving the same singles or peaks are the equivalent protons.

Step 2: Signal production

All equivalent proton produces a single signal and all the non-equivalent proton produces a separate signal for each proton.

Step 3: Signal splitting

As the signal is produced by the proton is divided into subparts like 1H atom produce multiplet due to the different environment

If a methyl group is surrounded by other methyl groups produces a doublet.

Or some produce quartet signal.

Step 4: The signal splitting of compound A

As per the molecule shown below the carbon represented by 1 produces a triplet due to methyl having three hydrogens.

Carbon is represented by two produce quartets because two hydrogens of methylene share different environments.

Carbon is represented by three produce septet due to 1 hydrogen share by 2 methyl groups.

Carbon represented by four produces doublet due to the six hydrogen.

Given Compound