Q12DQ - University Physics with Modern Physics

Question

There appears to be anambiguity for the case s = 10cm to whether s′ is $\mathbf{s}\mathbf{\text{'}}\mathbf{=}\mathbf{+}\mathbf{\infty }$and $\mathbf{-}\mathbf{\infty }$ whether the image is erect or inverted. How is this resolved? Or is it?

Step-by-Step Solution

Answer

Yes, both cases are hold.

Step 1: Definition of mirror

The term mirror may be defined as a special type of glass that used to see what behind you.

Step 2: Explain reason of question

There is no image formed when s = f reflected rays and axis have angle zero degree. s > f  in that case real image larger and farmer from the mirror. s' is larger and positive when $\mathrm{s}\to \mathrm{f}$ . s < f in that case virtual image larger and farther from the mirror.is negative and magnitude larger when $\mathrm{s}\to \mathrm{f}$.

Hence, yes these both cases are hold.