Q12CP - Chemistry: Molecular Nature Of Matter And Change

Question

Balance each reaction and write its reaction quotient, ${\mathbf{Q}}_{\mathbf{c}}$:

$$\begin{gathered} \mathbf{\left(}\mathbf{a}\mathbf{\right)}\mathbf{ }\mathbf{NO}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{+}{\mathbf{O}}_{\mathbf{2}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{ }\mathbf{ }\mathbf{𝆏}\mathbf{ }\mathbf{ }{\mathbf{N}}_{\mathbf{2}}{\mathbf{O}}_{\mathbf{3}}\mathbf{\left(}\mathbf{g}\mathbf{\right)} \\ \mathbf{\left(}\mathbf{b}\mathbf{\right)}\mathbf{ }{\mathbf{SF}}_{\mathbf{6}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{+}{\mathbf{SO}}_{\mathbf{3}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{ }\mathbf{ }\mathbf{𝆏}\mathbf{ }\mathbf{ }{\mathbf{SO}}_{\mathbf{2}}{\mathbf{F}}_{\mathbf{2}}\mathbf{\left(}\mathbf{g}\mathbf{\right)} \\ \mathbf{\left(}\mathbf{c}\mathbf{\right)}\mathbf{ }{\mathbf{SCIF}}_{\mathbf{5}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{+}{\mathbf{H}}_{\mathbf{2}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{ }\mathbf{ }\mathbf{𝆏}\mathbf{ }\mathbf{ }{\mathbf{S}}_{\mathbf{2}}{\mathbf{F}}_{\mathbf{10}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{+}\mathbf{HCI}\mathbf{\left(}\mathbf{g}\mathbf{\right)} \end{gathered}$$

Step-by-Step Solution

Answer

The answer is,

$$\begin{gathered} \left(\mathrm{a}\right) 4\mathrm{NO}\left(\mathrm{g}\right)+{\mathrm{O}}_2\left(\mathrm{g}\right) 𝆏 2{\mathrm{N}}_2{\mathrm{O}}_3\left(\mathrm{g}\right),Q=\frac{{\left[{\mathrm{N}}_2{\mathrm{O}}_3\right]}^2}{{\left[\mathrm{NO}\right]}^4\left[{\mathrm{O}}_2\right]} \\ \left(\mathrm{b}\right) {\mathrm{SF}}_6\left(\mathrm{g}\right)+2{\mathrm{SO}}_3\left(\mathrm{g}\right) 𝆏 3{\mathrm{SO}}_2{\mathrm{F}}_2\left(\mathrm{g}\right),Q=\frac{{\left[{\mathrm{SO}}_2{\mathrm{F}}_2\right]}^3}{{\left[{\mathrm{SO}}_3\right]}^2\left[{\mathrm{SF}}_6\right]} \\ \left(\mathrm{c}\right) 2{\mathrm{SCIF}}_5\left(\mathrm{g}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right) 𝆏 {\mathrm{S}}_2{\mathrm{F}}_{10}\left(\mathrm{g}\right)+2\mathrm{HCI}\left(\mathrm{g}\right),Q=\frac{[ {\mathrm{S}}_2{\mathrm{F}}_{10}]{\left[\mathrm{HCI}\right]}^2}{{\left[{\mathrm{SCIF}}_5\right]}^2\left[{\mathrm{H}}_2\right]} \end{gathered}$$

Step 1: Reaction quotient

The Reaction quotient of a reaction is the ratio of the concentration of reactants and products raised to their stoichiometry in the reaction equation. The reaction quotient and the equilibrium constant are equal when the reaction is at equilibrium

Step 2: Subpart (a)

The given reaction is balanced as shown below.

$4\mathrm{NO}\left(\mathrm{g}\right)+{\mathrm{O}}_2\left(\mathrm{g}\right) 𝆏 2{\mathrm{N}}_2{\mathrm{O}}_3\left(\mathrm{g}\right)$

The reaction quotient for the above reaction is as shown below.

$Q=\frac{{\left[{\mathrm{N}}_2{\mathrm{O}}_3\right]}^2}{{\left[\mathrm{NO}\right]}^4\left[{\mathrm{O}}_2\right]}$

The reaction quotient is represented using the letter Q which can be written as similar to the equilibrium constant.

Step 3: Subpart (b)

The given reaction is balanced as shown below.

${\mathrm{SF}}_6\left(\mathrm{g}\right)+2{\mathrm{SO}}_3\left(\mathrm{g}\right) 𝆏 3{\mathrm{SO}}_2{\mathrm{F}}_2\left(\mathrm{g}\right)$

The reaction quotient for the above reaction is as shown below.

$Q=\frac{{\left[{\mathrm{SO}}_2{\mathrm{F}}_2\right]}^3}{{\left[{\mathrm{SO}}_3\right]}^2\left[{\mathrm{SF}}_6\right]}$

The reaction quotient is represented using the letter Q which can be written as similar to the equilibrium constant.

Step 4: Subpart (c)

The given reaction is balanced as shown below.

$2{\mathrm{SCIF}}_5\left(\mathrm{g}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right) 𝆏 {\mathrm{S}}_2{\mathrm{F}}_{10}\left(\mathrm{g}\right)+2\mathrm{HCI}\left(\mathrm{g}\right)$

The reaction quotient for the above reaction is as shown below.

$Q=\frac{[ {\mathrm{S}}_2{\mathrm{F}}_{10}]{\left[\mathrm{HCI}\right]}^2}{{\left[{\mathrm{SCIF}}_5\right]}^2\left[{\mathrm{H}}_2\right]}$

The reaction quotient is represented using the letter Q which can be written as similar to the equilibrium constant.