Q125P

Question

An octahedral complex with three different ligands can have formulas with three different ratios of the ligands: 

MA4BC4+, such as CoNH34H2OCl2+

MA3B2C2+, such Cr(H2O3Br2Cl

MA2B2C2*+, such as CrNH32H2O2Br2+

Step-by-Step Solution

Verified
Answer

(I) tetraammineaquachlorocobalt (III), with cis/trans isomers;

(2) aquatribromodichlorochromium(III), with fac/mer isomers;

(3) diamminediaquadibromochromium(III), with cis/trans isomers;

1Step 1: Given information

The given information is to find the formula of coordination compounds.

2Step 3: Solve the given statements


In naming coordinate compounds, it is important to follow conventions:

- Cations are named before anions

- The ligands are arranged alphabetically

- The name of the metal ion comes last, while the charge of the ion must be enclosed in parenthese

- When the overall charge of the complex ion is negative, the metal must end in -ate

MA4BCn+:CoNH34H2OCl2+

Ligands:4NH3 ammine,1H2O aqua,1Cl- chloro

Name: tetraammineaquachlorocobalt(III)

Isomers: Geometric Isomers.


 

 

 

MA3B2Cn+:CrH2O3BrCl

Ligands: (3Br-  bromo,H2O aqua, (2Cl- chloro

Name: aquatribromodichlorochromium(III)

Isomers: Fac/Mer isomers




 

MA2B2C2n+:CrNH32H2O2Br2+

Ligands: ammine, aqua, bromo

Name: diamminediaquadibromochromium(III)

Isomers: cis/trans isomers