Q12. - Algebra 1

Question

Write an equation in point-slope form for the line that passes through each point with the given slope.

$\left(1,4\right),m=6$

Step-by-Step Solution

Answer

The equation of the straight line for the given condition is $\mathit{y}\mathbf{=}\mathbf{6}\mathit{x}\mathbf{-}\mathbf{2}$.

Step 1. State the concept of a straight line.

The standard form of slope and intercept form of the straight line is $y=mx+c$.

Here, $m$ is the slope of the straight line and $c$ is the $y$-intercept of the equation.

Step 2. State the equation of a line slope-point form.

The standard form of slope and point form of the straight line is $y-y_1=m\left(x-x_1\right)$

Here $m$ is the slope of the straight line and is the point from which the straight line passes.

$$\begin{gathered} \left(x_1,y_1\right)=\left(1,4\right) \\ m=6 \end{gathered}$$

Step 3. Substitute the values to get the required equation.

Substitute the above values in the equation $y-y_1=m\left(x-x_1\right)$

$$\begin{gathered} y-y_1=m\left(x-x_1\right) \\ y-4=6\left(x-1\right) \\ y-4+4=6x-6+4 \\ y=6x-2 \end{gathered}$$

The equation of the straight line is $y=6x-2$.