Q12. - Algebra 2

Question

If $\mathbf{n}$ and $\mathbf{p}$ are each different positive integers and $\mathbf{n}\mathbf{+}\mathbf{p}\mathbf{=}\mathbf{4}$, what is one possible value of $\mathbf{3}\mathbf{n}\mathbf{+}\mathbf{4}\mathbf{p}$?

Step-by-Step Solution

Answer

The one possible value of $3n+4p$ is 15.

Step 1 ­- Description of step.

It is given that n and p are each different positive integers and $n+p=4$.

Therefore, let the value of n be 1.

Now, the value of p is given by:

$\begin{array}{c}n+p=4\\ 1+p=4\\ p=4-1\\ p=3\end{array}$

Therefore, the values of $n$ and $p$ are 1 and 3 respectively.

Step 2 ­- Description of step.

Find the value of $3n+4p$ by substituting 1 for n and 3 for p.

Therefore, it can be obtained that:

$\begin{array}{c}3n+4p=3\left(1\right)+4\left(3\right)\\ =3+12\\ =15\end{array}$

Therefore, the value of $3n+4p$ is 15.

Step 3 ­- Description of step.

Therefore, one of the possible value of $3n+4p$ is 15.