Q12. - Algebra 2

Question

For Exercises 12-14, use the table that shows the temperatures at different times on March 23, 2002.

What was the average rate of change of the temperature from 8:00 A.M. to 10:00 A.M.?

Step-by-Step Solution

Answer

The average rate of change of the temperature from 8:00 A.M. to 10:00 A.M. is $5.5^o$. 

Step 1- Given information

Table of the data,

Step 2- Formula used

The slope formula (rate of change) m of a line is:

$m=\frac{y_2-y_1}{x_2-x_1}$

Where, m is slope of the line which is passes through the points $(x_1,y_1),(x_2,y_2)\text{ and }{x}_1\ne x_2.$

Step 3- To find the Rate of change

Here, $(x_1,y_1)=(8,36){\text{ and (x}}_2,y_2)=(10,47)$

So,  $m=\frac{y_2-y_1}{x_2-x_1}$

 $\begin{array}{l}\Rightarrow m=\frac{47-36}{10-8}\\ \Rightarrow m=\frac{11}{2}\\ \Rightarrow m=5.5\end{array}$

Hence, the average rate of change of the temperature from 8:00 A.M. to 10:00 A.M. is $5.5^o$.