Q12. - Algebra 2

Question

Evaluate each expression $x=4,y=-2,$ if and $z=6$

$x+\left[3\left(y+z\right)-y\right]$

Step-by-Step Solution

Answer

Expression $x+\left[3\left(y+z\right)-y\right]$ results into 18.

Step 1 - Order of simplification

To evaluate any expression involving more than one operation, follow the below order of operations:

• First evaluate expressions inside grouping symbols like parentheses ( ) or brackets [ ].
• Evaluate the exponents.
• Perform Multiplication and division from left to right.
• Perform addition and subtraction from left to right.

Step 2 - Substitute given values

Simplify parentheses by adding $y$ with $z$. Then multiply result with 3 and subtract y from it. 

Finally add resultant with $x$.

Substitute 4 for $x$, $-2$ for $y$ and 6 for $z$  into given expression

 $x+\left[3\left(y+z\right)-y\right]=4+\left[3\left(\left(-2\right)+6\right)-\left(-2\right)\right]$

Step 3 - Simplify 4 + 3 - 2 + 6 - - 2

Follow order of simplification

$\left(-2\right)+6=4$

Then 

$3\left(4\right)=12$

Then 

 $12-\left(-2\right)=14$

Finally

 $4+14=18$

Thus,  $x+\left[3\left(y+z\right)-y\right]=18$