Q1.11P

Question

Find the gradients of the following functions:

(a)  f(x,y,z)=x4+y3+z4

(b)  f(x,y,z)=x2y3z4

(c) f(x,y,z)=exsin(y)ln(z) 

Step-by-Step Solution

Verified
Answer

(a) The gradient of the function is 2xx^+3y2y^+4z3z^.

(b) The gradient of the function is 2xx^+3y2y^+4z3z^ .

(c) The gradient of the function is exsinylnzx^+excosylnzy^+exsinyzz^.

1Step 1: Write the given information.

 

The given functions are,

(a)  fx,y,z=x4+y3+z4

(b)  fx,y,z=x2y3z4

(c)  fx,y,z=exsinylnz

2Step 2: Define gradient of the function.

The gradient of the function is defined as its slope on the curve of that function for the given particular point.

 

3Step 3: Solve for the gradient of part (a).

Write the given function.

 fx,y,z=x4+y3+z4

Differentiate the above function as,

 fx=2xfy=3y2fz=4z3

Then, the gradient of the function is written as,

 f=fxx^+fyy^+fzz^=2xx^+3y2y^+4z3z^

Therefore, the gradient of the function is 2xx^+3y2y^+4z3z^ .

4Step 4: Solve for the gradient of part (b).

Write the given function.

 fx,y,z=x2y3z4

Differentiate the above function as,

 fx=2xy2z4fy=3x2y2z4fz=4x2y3z3

Then, the gradient of the function is written as,

 f=fxx^+fyy^+fzz^=2xy2z4x^+3x2y2z4y^+4x2y3z3z^

Therefore, the gradient of the function is 2xx^+3y2y^+4z3z^.

5Step 5: Solve for the gradient of part (c).

Write the given function.

 fx,y,z=exsinylnz 

Differentiate the above function as,

 fx=exsinylnzfy=excosylnzfz=exsinyz

Then, the gradient of the function is written as,

 f=fxx^+fyy^+fzz^=exsinylnzx^+excosylnzy^+exsinyzz^ 

Therefore, the gradient of the function is .

 exsinylnzx^+excosylnzy^+exsinyzz^