Q11.
Question
Question: Draw the products of each reaction.
Step-by-Step Solution
Verified Answer
Answers
The products formed are shown below.
1Step 1: Halogenation
Halogenation is carried out by treating a carbonyl compound that can form enolates followed by an attack with a halogen in the presence of an acid.
2Step 2: Mechanism involved in the halogenation in acids
The first step involved is protonation. The second step is the formation of an enolate, followed by the third step that is the attack of an electrophile in the presence of an acid. The last step is deprotonation.
Representation of the halogenation in acids
3Step 3: The formation of products in the given reactions
Considering all the explanations, the alpha hydrogen in the given compound will be replaced with the halide, and the products formed are shown below.
Other exercises in this chapter
Q9.
Question: What enolate is formed when each ketone is treated with LDA in THF solution? What enolate is formed when these same ketones are treated with NaO
View solution Q10.
Question: Explain each observation: (a) When (R)-2-methylcyclohexanone is treated with NaOH in H2O , the optically active solution gradually loses optical
View solution Q12.
Question: Draw the products of each reaction. Assume excess halogen is present.
View solution Q13.
Question: Draw the organic products formed when 2-bromopentan-3-one ( CH3CH2COCHBrCH3) is treated with each reagent: (a) Li2CO3, LiBr, DMF; (b) CH3CH2NH2&n
View solution