Q11 E

Question



Use the mass-spring analogy to explain the qualitative nature of the solutions to the Rayleigh equation  (22) y-1-y'2y'+y=0depicted in Figures 4.24 and 4.25.







Step-by-Step Solution

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Answer

Therefore, the solution to the Rayleigh equation is we can expect a limit cycle.

1Step 1: General form

The Energy Integral Lemma: 

 

Let y(t) be a solution to the differential equation y=fy, where f(y) is a continuous function that does not depend on y’ or the independent variable t. Let F(y) is an indefinite integral of fy, that is, fy=ddyFy. Then the quantity is Et:=12y't2-Fytconstant; i.e., ddtEt=0 .

 Change of angular momentum: 

 m2θ=-mgsinθ …… (1)

 

Newton’s rotational law: The rate of change of angular momentum is equal to torque.

 The mass–spring oscillator equation:

 Fext=inertiay+dampingy'+stiffnessy=my+by'+ky…… (2)

2Step 2: Prove the given equation.

Given that, y-1-y'2y'+y=0 …… (3)

 

Compare equation (3) with equation (2).

 Then, m=1,b=y'2-1 and k=1.

 

And the damping coefficient is y'2-1. It indicates that low velocities are boosted and high velocities are slowed.

 

So, we can expect a limited cycle.