Q10.88 CP

Question

Oxalic acid (H2C2O4 ) is found in toxic concentrations in rhubarb leaves. The acid forms two ions, HC2O4- and C2O42- , by the sequential loss of H ions. Draw Lewis structures for the three species, and comment on the relative lengths and strengths of their carbon-oxygen bonds. The connections among the atoms are shown below with single bonds only.




Step-by-Step Solution

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Answer

The Lewis structure of (3) three species.

  1. Oxalic acid has two longer C-O bonds and two shorter C=O bonds. The C-OH bond is longer than C=O bond and C=O bond is stronger than C-OH bond.
  2. H atom has one long and weaker C-O bond and the other 3 are are short and stronger C=O bond in the  HC2O4 - . The bond order is 1.5.

  3. All C-O bonds are of equal bond length and strength in  C2O42-. The bond order of each is 1.5.

1Step 1: Definition

Lewis structures, also known as electron-dot structures or electron-dot diagrams, are diagrams that display the interactions between the atoms in a molecule as well as any potential lone pairs of electrons.

2Step 2: The Lewis structure of (3) three species.


3Step 4: The relative lengths and strengths of their carbon-oxygen bonds:



Resonance structures are collections of Lewis structures that explain how electrons in a molecule are delocalized.

  1. Oxalic acid is the simplest dicarboxylic acid. It has two C=O and two C-OH bonds. On the oxygen atoms of the carbonyl and hydroxyl groups, there are two lone pairs. Oxalic Acid has two longer C-O bond and two shorter C=O bond.

  2. Due to resonance the side of the molecule with H atom have one long CO bond and 1 short C=O bond. On the other side the bond lengths are smaller than the other side. The bond order is 1.5. Resonance structures of HC2O4 - are as follow


      c. All the carbon-oxygen bonds are of equal bond length. The bond order of each is 1.5. The            resonance structures of C2O42- are as follows.