Q10.71CP

Question

Chloral, Cl3CCH=O , reacts with water to form the sedative and hypnotic agent chloral hydrate,  Cl3CCH(OH)2  . Draw Lewis structures for these substances, and describe the change in molecular shape, if any, that occurs around each of the carbon atoms during the reaction.

 

Step-by-Step Solution

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Answer


The Lewis structures for the given substances.





The change in molecular shape:

Here, the sp2  carbon (in chloral) changes to   sp3 carbon (in chloral hydrate) and the bond angle changes from  120° to  109.5°.

 

1Step 1: Structure of chloral.


In chloral, one carbon is attached with three chlorine atoms and one carbon atom. hence the hybridization of this carbon is sp3  and the geometry will be tetrahedral. Another carbon atom is bonded with one hydrogen and one carbon atom with a single bond and with one oxygen atom with a double bond. Hence the hybridization of this carbon is  sp2 and the geometry will be trigonal planar. 

 

The bond angle is   120°.

 


2Step 2: Structure of chloral hydrate


In chlorate hydrate one carbon is attached with three chlorine atoms and one carbon atom. Hence the hybridization of this carbon is sp3  and the geometry will be tetrahedral. Other carbon atom is bonded with two -OH group, one carbon atom, and one hydrogen atom. Hence the hybridization is  sp2  and the geometry will be tetrahedral.

 

The bond angle is   109.5°.




3Step 3: Deviations or the change in molecular shape.

The sp2  carbon of chloral changes to  sp3 carbon in chloral hydrate and the bond angle changes from 120°  to 109.5° .

So, the geometry changes form trigonal planar to tetrahedral.