Q10. - Algebra 1

Question

Graph each equation.

$\mathbf{15}\mathit{y}\mathbf{=}\mathbf{3}$

Step-by-Step Solution

Answer

The table of values for the points $(x,y)$ for the equation $y=\frac{1}{5}$ is:

$x$	$y$	$(x,y)$
$-2$	$\frac{1}{5}$	$\left(-2,\frac{{\displaystyle 1}}{{\displaystyle 5}}\right)$
0	$\frac{1}{5}$	$\left(0,\frac{{\displaystyle 1}}{{\displaystyle 5}}\right)$
$-1$	$\frac{1}{5}$	$\left(-1,\frac{{\displaystyle 1}}{{\displaystyle 5}}\right)$
2	$\frac{1}{5}$	$\left(2,\frac{{\displaystyle 1}}{{\displaystyle 5}}\right)$

The graph of the equation $y=\frac{1}{5}$ is:

Step 1. Rewrite the given equation 15 y = 3 .

The given equation $15y=3$ can be written as:

$\begin{array}{c}15y=3\\ y=\frac{3}{15}\\ y=\frac{1}{5}\end{array}$

Step 2. Make a table of values for the points ( x , y ) for the equation y = 1 5 .

The table of values for the points $(x,y)$ for the equation $y=\frac{1}{5}$ is:

$x$	$y$	$(x,y)$
$-2$	$\frac{1}{5}$	$\left(-2,\frac{{\displaystyle 1}}{{\displaystyle 5}}\right)$
0	$\frac{1}{5}$	$\left(0,\frac{{\displaystyle 1}}{{\displaystyle 5}}\right)$
$-1$	$\frac{1}{5}$	$\left(-1,\frac{{\displaystyle 1}}{{\displaystyle 5}}\right)$
2	$\frac{1}{5}$	$\left(2,\frac{{\displaystyle 1}}{{\displaystyle 5}}\right)$

Step 3. Graph the equation y = 1 5 .

The plot of the points $(x,y)$is:

Draw the graph of the equation $y=\frac{1}{5}$ by joining the plotted points.

 

Therefore, the graph of the equation $y=\frac{1}{5}$ is: