Q10. - Algebra 1

Question

Evaluate the following expression:

$\frac{40-2^3}{4+3{\left(2\right)}^2}$

Step-by-Step Solution

Answer

The algebraic expression is: $\frac{40-2^3}{4+3{\left(2\right)}^3}=\frac{32}{28}$.

Step 1. Given information.

The expression is:

$\frac{40-2^3}{4+3{\left(2\right)}^3}$

Step 2. Write the concept.

Use the formula such that, $a^3=a\times a\times a$.

The BODMAS rule is according to the following order to solve the expression:

$\mathrm{Brackets}\to \mathrm{Division}\to \mathrm{Multiplication}\to \mathrm{Addition}\to \mathrm{Subtraction}$

Step 3. Solve the expression.

The expression $\frac{40-2^3}{4+3{\left(2\right)}^3}$ can be solved as in below.

$$\begin{gathered} \frac{40-2^3}{4+3{\left(2\right)}^3}=\frac{40-2\times 2\times 2}{4+3\left(2\times 2\times 2\right)} \\ =\frac{40-8}{4+3\left(8\right)} \\ =\frac{32}{4+24} \\ =\frac{32}{28} \end{gathered}$$