Q. 9.80

Question

Select the container that represents the dilution of a 4%(m/v) KCl solution to give each of the following: (9.5)

a. a 2%(m/v) KCl solution

b. a 1%(m/v) KCl solution

               

Step-by-Step Solution

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Answer

(part a) As a conclusion, container 2 shows a dilution of a4%(m/v) KClsolution to a 2%(m/v) KCl solution.

(part b) As an outcome, container 3 represents a dilution of a 4%(m/v) KClsolution to a 1%(m/v) KCl solution.

1Step 1: Introduction (part a)

Dilution is the process of lowering the amount of solute in a solution by adding extra more solvent to the solution, such as water.

2Step 2: Given data (Part a).

(part a) The solute has a dark hue, whereas the colour of the solution illuminates during dilution. We already know that the amount of solute in a pure solvent is the same as in a diluted solution. As a result, we have the following dilution expression:

C1V1=C2V2

The 4% KCl liquid has a dark blue colour. A 2%(m/v) KCl liquid has a content of half that of a 4%(m/v) KCl solution.

3Step 3: Explanation (Part a).


(part a) As a result, the ultimate volume of a 2%(m/v) KClsolution ought to be roughly twice as high a 4%(m/v) KCl solution.

The concentration of the solution in container 2 is nearly twice that of the 4% KCl solution.

As a result, container 2 illustrates the dilution of a 4%(m/v) KCl solution to a 2%(m/v) KCl solution.



4Step 4: Given data (Part b).

(part b) The 4%KCl fluid has a dark blue colour. A 2%(m/v) KCl solution has a content of half that of a 4%(m/v) KClsolution.

5Step 5: Explanation (Part b).


(part b) As a result, the ultimate volume of a 1%(m/v) KCl solution should just be roughly double what it was a 4%(m/v) KCl solution.

The solution in container 3 has a volume four times that of the 4% KClsolution.

As a result, container 3 depicts a 4%(m/v) KCl solution diluted to 1%(m/v) KCl solution.