Q. 9.76 - An Introduction to General, Organic, and Biological Chemistry

Question

An intravenous solution of mannitol is used as a diuretic to increase the loss of sodium and chloride by a patient. If a patient receives $30.0 mL$ of a $25\% (m/v)$ mannitol solution, how many grams of mannitol were given?

Step-by-Step Solution

Answer

As an outcome, the patient's necessary mannitol mass is $7.5 g.$

Step 1: Introduction.

Every diuretic works on a separate portion of your kidneys. Some drugs contain and over one kind of diuretic or a diuretics in concert with some other heart rate drug.

Step 2: Given data.

Using the mass by volume percent equation, determine the mass of mannitol.

$Mass volume percent(m/v)=\frac{mass of solute }{volume of solution}\times 100\%$

Volume of injectable mannitol liquid delivered to the patient$30.0 mL$. Mass /volume percent of mannitol solution $25\% (m/v)$, which equals $25 mL$, as per the problem.

Step 3: Explanation.

In the provided phrase, substitute the above values.

$Mass volume percent(m/v)=\frac{mass of solute }{volume of solution}\times 100\%$

$25\%=\frac{mass of solute}{30 mL}\times 100\%$

$Mass of solute=7.5 g$

As a result, the patient needs $7.5 g$ of mannitol.