Q. 9.72 - An Introduction to General, Organic, and Biological Chemistry

Question

Each of the following mixtures is placed in a dialyzing bag and immersed in distilled water. Which substances will be found outside the bag in the distilled water?

a. $KCl$ solution and glucose solution.

b. albumin solution (colloid).

c. albumin solution (colloid), $KCl$ solution, and glucose solution.

d. urea solution and $NaCl$ solution.

Step-by-Step Solution

Answer

(part a) As an outcome, $KCl$ and glucose will be present in the distilled water outside the bag.

(part b) In the pure water, no material will be detected outside the bag.

(part c) As a consequence, KCl and glucose would be found in plain water outside the bag.

(part d) As a result, urea and NaCl will be identified in the deionized outside the bag.

Step 1: Introduction (Part a).

Dialysis bags have a medium that permits ions and tiny molecules such as sugars and proteins to pass across. Proteins and carbohydrates, on the other hand, are too big to pass through the dihydrate membrane.

Step 2: Given data(Part a).

The drug will be discovered in distilled water outside the bag.

$KCl$ solution and glucose solution.

Step 3: Explanation(Part a).

The dialyzing bag basically allows species such as $K^{+}ion$, $C{l}^{-}ion$, and glucose molecules can pass through.

As a result, $KCl$ and glucose will be present in the pure water outside the bag.

Step 4: Given data(Part b).

The drug will be discovered in distilled water outside the bag.

Albumin solution (colloid). 

Step 5: Explanation (Part b).

Bigger molecules or ions cannot flow through the semi-permeable layer in colloids. A colloid, such as albumin, cannot flow through all the dihydrate bag. As a result, no material will be found in the distilled water outside of the bag.

Step 6: Given Data(Part c).

The drug will be discovered in distilled water outside the bag.

Albumin solution (colloid),  solution, and glucose solution. 

Step 7: Explanation (Part c).

Albumin stays inside the dihydrate bag, but $K^{+}ion$, $C{l}^{-}ion$, and sugar molecules pass through. As a result, $KCl$and glucose will be discovered in distilled water from outside bag.

Step 8: Given data (Part d).

The drug will be discovered in distilled water outside the bag.

Urea solution and $NaCl$ solution.

Step 9: Explanation (Part d).

Urea, $N{a}^{+}$ions, and $C{l}^{-}$ions molecules will flow through the dihydrate bag. The filtered water will include So, urea, and $NaCl$ outside the bag.