Q. 9.61 - An Introduction to General, Organic, and Biological Chemistry

Question

You need $500 mL$of a $5.0\% (m/v)$ glucose solution. If you have a $25\% (m/v)$ glucose solution on hand, how many milliliters do you need?

Step-by-Step Solution

Answer

Volume of the glucose is $1.0\times {10}^2 mL$ if you have a $25\% (m/v)$glucose solution.

Step1: Introduction.

To finish a quality control on your blood glucose monitoring, use glucose control solution. It can assist you in determining whether your meter and test strips are working properly.

Step2: Given Information.

The following are the given information:

We have $500 mL$ of a $5.0\% (m/v)$ glucose solution.

Find for $25\% (m/v)$ glucose solution.

Step3: Find the mass of the glucose.

$\text{ Mass / Volume percent }(\mathrm{m}/\mathrm{v})=\left(\text{ Mass of solute / Volume of solution }\right)\times 100\%$

$\text{ Mass / Volume percent of the glucose solution to be prepared }=5.0\%( \mathrm{m}/\mathrm{v})$

Volume of the solution is $500 mL.$

Mass of the glucose is,

$$\begin{gathered} =(\text{ Mass }/\text{ Volume percent }\times \text{ Volume of the solution })/100\% \\ =(5.0\%\times 500)/100\% \\ =25 g \end{gathered}$$

Step4: Find the volume of the glucose.

Mass of the glucose is $25 g$

$\text{ Mass / Volume percent of the stock solution }=25\%( \mathrm{m}/\mathrm{v})$

Therefore,

The volume of the glucose is,

$$\begin{gathered} =\left(\text{ Mass of glucose in the solution / Mass / Volume percent of the solution }\right)\times 100\% \\ =(25/25\%)\times 100\% mL \\ =100 mL \\ =1.0\times {10}^2 mL \end{gathered}$$

Hence the volume of the glucose is $1.0\times {10}^2 mL$