Q. 9.6

Question

Water is a polar solvent and hexane $C_{6} H_{14}$ is a nonpolar solvent. In which solvent is each of the following, which is found or used in the body, more likely to be soluble?

a. vegetable oil, nonpolar

b. oleic acid (lipid), nonpolar

c. niacin (vitamin $B_{3}$ ), polar

d. $F e S O_{4}$ (iron supplement), ionic

Step-by-Step Solution

Verified

Answer

(a) Vegetable oil, nonpolar and is soluble in Hexane $(C_{6} H_{14})$

(b) Oleic acid (lipid), non polar and i soluble in Hexane $(C_{6} H_{14})$

(d) $F e S O_{4}$ (iron supplement), ionic and is soluble in water.

1Step1: Introduction.

Two hydrogen atoms and one electronegative oxygen atom end up making up a water molecule. Due to the obvious differential in electronegativity values, either every hydrogen atom attains a partial positive charge, while the oxygen atom achieves a partial negative charge.

2Step2: Hexane.

There really is no electronegative particle in the hexane molecule. The bond $C - H$ is nonpolar. As just a result, hexane is a nonpolar solvent and it will dissolve only nonpolar compounds.

3Step3: Given Information (part a).

Water is a polar solvent and Hexane $(C_{6} H_{14})$ is a non-polar solvent.

To find the Vegetable oil, polar is soluble or not.

4Step4: Explanation (part a).

Vegetable oil is nonpolar and hexane $(C_{6} H_{14})$ soluble.

5Step5: Given Information (part b).

Water is a polar solvent and Hexane $(C_{6} H_{14})$ is a non-polar solvent.

To know the oleic acid (lipid), non polar is soluble or not.

6Step6: Explanation (part b).

Oleic acid is a nonpolar compound that is soluble in hexane $(C_{6} H_{14})$ .

7Step7: Given Information (part c).

Water is a polar solvent and Hexane $(C_{6} H_{14})$ is a non-polar solvent.