Q. 9.52 - An Introduction to General, Organic, and Biological Chemistry

Question

A patient receives $250 mL of a 4.0\% (m/v)$ amino acid solution twice a day.

a. How many grams of amino acids are in $250 mL$ of solution?

b. How many grams of amino acids does the patient receive in $1$ day?

Step-by-Step Solution

Answer

(part a) $10 \mathrm{g}\text{ amino }a\text{cids }$present in the $250 mL$ of the given solution.

(part b) $20 \mathrm{g} \mathrm{of}\text{ amino }a\text{cids }$does the patient receive in one day.

Step1: Introduction (part a).

Amino acids are considered that specimens when they combine. The conditions for life are amino acids and proteins.

Step2: Given Information (part a).

The following details are provided:

A patient receiving $250 mL of a 4.0\% (m/v)$ amino acid solution.

Step3: Explanation (part b).

Find the grams of amino acid present in $250 mL$ of solution,

$100 \mathrm{ml}\text{ solution }=4.0 \mathrm{g}\text{ amino }acids$

$\frac{4.0 \mathrm{g}\text{ aminoacids }}{100 \mathrm{ml}\text{ solution }}\text{ and }\frac{100 \mathrm{mlsolution}}{4.0 \mathrm{g}\text{ aminoacids }}$

Rewrite the formula,

$$\begin{gathered} =250 \mathrm{ml}\text{ sotition }\times \frac{4.0 \mathrm{g} a\text{minoacids }}{100 \mathrm{ml}\text{ sotution }} \\ =10 \mathrm{g}\text{ amino }a\text{cids } \end{gathered}$$

Step4: Given Information (part b).

The following details are provided:

A patient who is receiving$250 mL of a 4.0\% (m/v)$ amino acid solution.

Step5: Explanation (part b).

Since then, the patient has received $10 g$ of amino acids double the a day. 

Hence, the patient receives amino acids.

$$\begin{gathered} 1 day=2\times 10 g \\ =20 g \end{gathered}$$