Q. 9.38 - An Introduction to General, Organic, and Biological Chemistry

Question

What is the difference between a $10.0\% (v/v)$ methanol $\left(C{H}_{4}O\right)$ solution and a $10.0\% (m/m)$ methanol solution?

Step-by-Step Solution

Answer

The difference between both the methanol solution is,

$10.0\% (v/v)$ methanol solution is $10 mL$ solute in $100 mL$ of a solution.

$10.0\% (m/m)$ methanol solution indicates $10 g$ solute in $90 g$ of water.

Step 1: Given Information.

The following are the given information to find the difference of the Methanol solution is as follows:

$10.0\% (v/v)$ and $10.0\% (m/m)$ methanol solution.

Step 2: Find the Volume percent.

Using the following expression, compute the volume percent.

$\text{ Volume percent }(\mathrm{v}/\mathrm{v})=\frac{\text{ Solute volume }}{\text{ Solution volume }}\times 100\mathrm{\%}$

$10 mL$ of solute methanol throughout $100 mL$ of solution equals $10.0\% (v/v)$ methanol solution.

Step 3: Find the Mass percent.

By using following equation, find the mass present.

$\text{ Mass percent }(\mathrm{v}/\mathrm{v})=\frac{\text{ Solute}\text{ mass}}{\text{ Solution}\text{ mass}}\times 100\mathrm{\%}$

$10 g$ of solute methanol present in $90 g$ of water equals $10.0\% (m/m)$ methanol solution.