Q. 9.2 - An Introduction to General, Organic, and Biological Chemistry

Question

Identify the solute and the solvent in each solution composed of the following:

a. $10.0 mL$ of acetic acid and $200 mL$ of water

b. $100.0 mL$ of water and $5.0 g$ of sugar

c. $1.0 g$ of $B{r}_2$ and $50.0 mL$ of methylene chloride $\left(l\right)$

Step-by-Step Solution

Answer

(part a) $10.0 mL$ of Acetic acid is the Solute and $200 mL$ of water is the Solvent.

(part b) $100 mL$ of Water is the Solvent and $5.0 g$ of sugar is the Solute.

(part c) $1.0 g$ of $B{r}_2$ is the Solute and $50.0 mL$ of Methylene chloride is the Solvent.

Step1: Introduction (part a)

A mixture up of two or more types of material in any ratio. There seem to be two main types of mixtures:

• Homogeneous mix

It is also recognized as a solution, so because substance composition is homogeneous.

• Heterogeneous combination

The structure of the material is not consistent throughout this shape of mixture, as well as the component of the mixture is viewable.

Step2: Given Information (part a).

$10.0 mL$ of acetic acid and $200 mL$ of Water.

To find the Solute and Solvent in the solution.

Step3: Explanation (part a).

In the solution; the major component is usually called the solvent, and the minor components are called the solutes.

Hence, $10.0 mL$ of  acetic acid is solute and $100 mL$ of water is solvent.

Step4: Given Information (part b).

$100 mL$ of water and $5.0 g$ of sugar to find out the Solute and the Solvent.

Step5: Explanation (part b).

In a solution, this same major element is usually referred to as the solvent, as well as the minor elements are referred to as the solutes; 

Thereby also, sugar is a Solute and water is a Solvent.

Step6: Given Information (part c).

$1.0 g$of Bromine$\left(B{r}_2\right)$ and $50.0 mL$ of Methylene Chloride.

To find the Solute and Solvent in the given solution.

Step7: Explanation (part c).

In a solution, the major component is usually referred to as the solvent, and also the minor components are referred to as the solutes; 

Thereby the, Bromine$\left(B{r}_2\right)$ is a Solute and Methylene chloride is a Solvent.