Q. 9 - Precalculus Enhanced with Graphing Utilities

Question

In Problems 7–18, match each graph to one of the following functions:

$$\begin{gathered} \mathit{A}\mathbf{.} y = x^2+ 2 \mathit{B}\mathbf{.} y = -x^2 + 2 \mathit{C}. y = \left|x\right| + 2 \\ \mathit{D}\mathbf{.} y = -\left|x\right|+ 2 \mathit{E}\mathbf{.} y = {(x - 2)}^2 \mathit{F}\mathbf{.} y = -{(x + 2)}^2 \\ \mathit{G}\mathbf{.} y = \left|x-2\right| \mathit{H}\mathbf{.} y = -\left|x+2\right| \mathit{I}\mathbf{.} y = 2x^2 \\ \mathit{J}\mathbf{.} y = -2x^2 \mathit{K}\mathbf{.} y = 2\left|x\right| \mathit{L}\mathbf{.} y = -2\left|x\right| \end{gathered}$$

Step-by-Step Solution

Answer

The given graph is matched to the function $\mathit{H}\mathbf{.}\mathbf{ }y=-\left|x+2\right|.$

Step 1. Given Information

There is the given graph we have to match each graph to its functions. 

Step 2. Identifying the function of the graph

When the right side of the function $y=f\left(x\right)$ is multiplied by $-1$ the graph of the new function $y=-f\left(x\right)$ is the reflection about the x-axis of the graph of the function $y=f\left(x\right)$.

Thus, the function whose graph is the reflection of the graph of $y=\left|x\right|$ in the x-axis is $y=-\left|x\right|.$

Step 3. Stating the function of the graph

If the argument x of a function f is replaced by $x+h, h>0,$ the graph of the

new function $y=f(x+h)$ is the graph of f  shifted horizontally left h units.

Since the graph of $y=-\left|x\right|$ is shifted horizontally left by $2$ units

The function of the given graph is $y=-\left|x+2\right|.$