Q. 84

Question

Use the Squeeze Theorem to find each of the limits in Exercises. Explain exactly how the Squeeze Theorem applies in each case.

 lim  x1(x-1)2cos1x-1

Step-by-Step Solution

Verified
Answer

The limit of the equation  lim  x1(x-1)2cos1x-1 is 0

1Step 1. Given Information:

 lim  x1(x-1)2cos1x-1

2Step 2. Applying Squeeze theorem on the limit:

By applying the Squeeze theorem;

Range of cos1x-1 "or cos x" is [-1,1]-1cos1x-11Now multiplying (x-1)2 on all side;-(x-1)2(x-1)2cos1x-1(x-1)2-(x2-2x+1)(x-1)2cos1x-1x2-2x+1-x2+2x-1(x-1)2cos1x-1x2-2x+1Applying limits on all side as x1;limx1-x2+2x-1limx1(x2-2x+1)cos1x-1limx1x2-2x+1-1+2-1(1-2+1)cos11-11-2+100(cos 0)0000so, lim  x1(x-1)2cos1x-1=0

3Step 3. Graph Representation: